Polynomials — Class 10 (Comprehensive Notes)

Factor theorem • Remainder theorem • Factorisation • Graphs • Practice
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1. What is a Polynomial?

A polynomial in variable x is an expression of the form anxn + an-1xn-1 + ... + a1x + a0, where coefficients ai are real numbers and n is a non-negative integer.

Degree: The highest power of x with a non-zero coefficient. If an ≠ 0, degree = n. Constant non-zero polynomial has degree 0; zero polynomial has undefined (or −∞) degree.

2. Types of Polynomials (by degree)

DegreeNameExample
0Constant5
1Linear2x + 3
2Quadraticx² − 5x + 6
3Cubicx³ − x² + 2

3. Remainder Theorem

If a polynomial f(x) is divided by (x − c), the remainder is f(c).

Example. Find remainder when f(x)=x³−2x²+3x−5 is divided by (x−2).

Compute f(2)=8−8+6−5=1 ⇒ remainder = 1.

4. Factor Theorem

(x − c) is a factor of f(x) iff f(c) = 0. Use this to test roots and factor polynomials.

Example. Show (x−3) is a factor of f(x)=x³−6x²+11x−6.

f(3)=27−54+33−6=0 ⇒ (x−3) is a factor. Divide to factor fully: f(x)=(x−3)(x−2)(x−1).

5. Factorisation Methods

  1. By factor theorem: Find rational roots c using Rational Root Theorem and test f(c)=0.
  2. Grouping: Group terms and factor common factors.
  3. Quadratic formula: For degree 2, use ax²+bx+c = 0 ⇒ x = [−b ± √(b²−4ac)]/(2a).
  4. Special products: a²−b²=(a−b)(a+b), a³±b³=(a±b)(a²∓ab+b²).

6. Graphs & Behaviour

Polynomial graphs are smooth and continuous. End behaviour depends on degree and leading coefficient:

  • Even degree, positive leading coef → both ends up.
  • Even degree, negative leading coef → both ends down.
  • Odd degree, positive leading coef → left down, right up.
  • Odd degree, negative leading coef → left up, right down.

Roots correspond to x-intercepts; multiplicity affects crossing/touching.

7. Solved Examples

Example 1. Factorize x³−4x²−7x+10.

Try integer roots ±1,±2,±5,±10. f(1)=0 ⇒ (x−1) factor. Divide to get (x−1)(x²−3x−10) = (x−1)(x−5)(x+2).

Example 2. If f(x)=2x³+3x²−11x−6 and (x+2) is a factor, factorize fully.

Use synthetic division: dividing by (x+2) gives quadratic 2x²−x−3 → (2x+3)(x−1) ⇒ f(x)=(x+2)(2x+3)(x−1).

8. Practice Questions

  1. Find remainder when x⁴−3x³+2x−5 is divided by (x−1). (Answer toggle)
  2. Factorize x³+6x²+11x+6.
  3. Show that (x−2) is a factor of x³−5x²+8x−4 and factorize fully.
  4. Find all real roots of 2x³−x²−8x+4.

9. Exam Tips & Tricks

  • Test small integer divisors of constant term (±1, ± factors) to find roots quickly.
  • Use synthetic division for speed.
  • Remember special products and grouping patterns.