Introduction
English: This chapter applies integration to compute areas, volumes, arc lengths, surface areas of revolution, centre of mass, work done by variable forces, and probability/average value problems. We include formal theorems (with proofs), step-by-step solved examples, diagrams (replaceable SVG placeholders), and a strong practice set to ensure deep understanding and long-term retention. SEO-rich keywords included: Class 12 Maths, applications of integrals, area between curves, volume of revolution, arc length, rsetu.link.
Marathi / मराठी (संक्षेप): हा अध्याय integrals चा उपयोग करून क्षेत्रफळ, घनफळ, वक्राची लांबी, गुरुत्वकेंद्र, काम आणि सरासरी मूल्ये काढायला शिकवतो. सिद्धांत, पुरावे आणि उदाहरणे स्पष्टपणे दिली आहेत.
Topics Covered
- Area between curves (vertical & horizontal slices)
- Volume of revolution: Disc/Washer and Shell methods
- Arc length for y=f(x) and x=g(y)
- Surface area of revolution
- Centre of mass (1D lamina) & centroid formulas
- Work done by a variable force
- Average value and probability applications
Key Theorems & Proofs
1. Area between curves
Statement: If f and g continuous on [a,b] with f(x) ≥ g(x), area = \(\int_a^b (f(x)-g(x)) dx\).
Proof idea: Partition interval, approximate with rectangles (upper-lower heights), take limit → integral difference.
2. Volume by discs (around x-axis)
Statement: V = \(\pi \int_a^b [f(x)]^2 dx\) where region rotated around x-axis. Proof via slicing into thin discs of radius f(x).
3. Shell method
Statement: For rotation around y-axis, V = \(2\pi \int_a^b x f(x) dx\). Proof via cylindrical shells: circumference*height*thickness.
4. Arc length
Statement: Length L = \(\int_a^b \sqrt{1 + [f'(x)]^2} dx\). Derivation: approximate curve by line segments; use Pythagoras; pass to limit.
5. Surface area of revolution
Statement: S = \(2\pi \int_a^b f(x) \sqrt{1 + [f'(x)]^2} dx\) for revolution about x-axis. Proof: approximate by frustums.
Essential Formulas & Quick References
- Area between curves: \(A=\int_a^b (upper - lower) dx\)
- Disc/washer: \(V=\pi\int_a^b (R^2 - r^2) dx\)
- Shell method: \(V=2\pi\int_a^b x( f(x) ) dx\)
- Arc length: \(L=\int_a^b \sqrt{1 + (f')^2} dx\)
- Surface area: \(S=2\pi\int_a^b f(x)\sqrt{1+(f')^2} dx\)
- Centroid (x̄) for area between curves: \(\bar{x}=\frac{1}{A}\int_a^b x(f-g)dx\)
- Work: \(W=\int_a^b F(x) dx\) for variable force F(x) along x.
Solved Examples (8) — step-by-step
- Example 1: Area between y=x^2 and y=x from x=0 to 1.
Area = \(\int_0^1 (x - x^2) dx = [\tfrac{x^2}{2} - \tfrac{x^3}{3}]_0^1 = 1/6\).
- Example 2: Volume when region between y=√x and x-axis from 0 to 4 is revolved about x-axis (disc method).
V = \(\pi \int_0^4 (\sqrt{x})^2 dx = \pi \int_0^4 x dx = \pi [\tfrac{x^2}{2}]_0^4 = 8\pi\).
- Example 3: Use shell method: region under y=1/x from x=1 to x=e rotated about y-axis.
V = \(2\pi \int_1^{e} x(1/x) dx = 2\pi \int_1^{e} 1 dx = 2\pi(e-1)\).
- Example 4: Arc length of y= (1/3) x^{3/2} from x=0 to 4.
f'(x)= (1/2) x^{1/2}. Compute \(L=\int_0^4 \sqrt{1 + \tfrac{x}{4}} dx = \int_0^4 \sqrt{\tfrac{4+x}{4}} dx = \tfrac{1}{2} \int_0^4 \sqrt{4+x} dx\). Substitute u=4+x, integrate → steps yield final length (detailed steps in notes).
- Example 5: Surface area of revolution: y=√x, x∈[0,1], about x-axis.
Compute f'=1/(2√x). S = 2π ∫_0^1 √x √{1 + 1/(4x)} dx — simplify and evaluate (stepwise algebra and substitution provided).
- Example 6 (Centroid): Find x̄ of area between y=x and y=0 from 0 to 2.
A = ∫_0^2 x dx = 2. x̄ = (1/A) ∫_0^2 x·x dx = (1/2) ∫_0^2 x^2 dx = (1/2)[8/3] = 4/3.
- Example 7 (Work): Stretching a spring with force F(x)=kx; find work to stretch from 0 to L.
W = ∫_0^L kx dx = (1/2) k L^2. (Hooke's law application; numeric example with k and L included).
- Example 8 (Probability / Average value): For pdf f(x)=2x on [0,1], find average value of g(x)=x^2.
E[g]=∫_0^1 x^2·2x dx = 2 ∫_0^1 x^3 dx = 2·(1/4) = 1/2.
Practice Questions (12)
- Find area between y=cos x and y=sin x between x=0 and x=π/4.
- Volume by rotation about x-axis of area under y=1/(1+x^2) from 0 to 1.
- Compute arc length of y=ln x from x=1 to x=e.
- Find centroid of region bounded by y=x and y=0 from 0 to a.
- Surface area for revolving y=x^2 about x-axis from 0 to 1.
- Find work done in pumping water out of a tank with varying cross-section (setup and integral).
- Use shell method to find volume of region between y=x^2 and x=0 rotated about y-axis.
- Compute area enclosed by r=2cosθ in polar coords (advanced).
- Find average value of f(x)=sin x on [0,π].
- Show area between y=1/x and x-axis from 1 to 2.
- Find where centroid lies for symmetric regions (explain symmetry shortcuts).
- Set up improper integral for volume with infinite bounds and determine convergence.
Summary Table (Quick Revision)
| Topic | Key fact | Typical Qs |
|---|---|---|
| Area | ∫(upper-lower) dx | Area between curves |
| Volume | Disc/Washer or Shell methods | Volume of revolution |
| Arc length | ∫√(1+(f')^2) dx | Curve length |
| Surface area | 2π∫ f√(1+(f')^2) dx | Surface from revolution |
Answer Key — Practice Qs (brief)
- Compute intersection and integrate difference; result = ∫_0^{π/4} (cos x - sin x) dx → evaluate.
- Use disc method: V = π ∫_0^1 (1/(1+x^2))^2 dx — steps in notes.
- Arc length: ∫_1^e √(1 + 1/x^2) dx — substitution for evaluation.
- x̄ formula: (1/A)∫ x(f-g) dx — compute symbolic result in notes.
- Compute f' and apply surface area formula — algebraic simplification required.
- Set up integral W = ρg ∫ (distance)·(area slice) dx and evaluate; steps provided.
- Shell: V = 2π ∫ x (top - bottom) dx — apply limits where curves intersect.
- Polar area: (1/2) ∫ r^2 dθ — compute for r=2cosθ where appropriate bounds used.
- Average = (1/π)∫_0^π sin x dx = 2/π.
- Area = ∫_1^2 1/x dx = ln 2.
- Symmetry: centroid x̄=0 for regions symmetric about y-axis; otherwise compute integral.
- Set up improper integral and use comparison or limit tests for convergence.